2 * Copyright (c) 2016 Thomas Pornin <pornin@bolet.org>
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29 br_i32_muladd_small(uint32_t *x
, uint32_t z
, const uint32_t *m
)
33 uint32_t a0
, a1
, b0
, hi
, g
, q
, tb
;
34 uint32_t chf
, clow
, under
, over
;
38 * We can test on the modulus bit length since we accept to
46 x
[1] = br_rem(x
[1], z
, m
[1]);
49 mlen
= (m_bitlen
+ 31) >> 5;
52 * Principle: we estimate the quotient (x*2^32+z)/m by
53 * doing a 64/32 division with the high words.
57 * a = (w*a0 + a1) * w^N + a2
66 * I.e. the two top words of a are a0:a1, the top word of b is
67 * b0, we ensured that b0 is "full" (high bit set), and a is
68 * such that the quotient q = a/b fits on one word (0 <= q < w).
70 * If a = b*q + r (with 0 <= r < q), we can estimate q by
71 * doing an Euclidean division on the top words:
72 * a0*w+a1 = b0*u + v (with 0 <= v < w)
73 * Then the following holds:
77 a0
= br_i32_word(x
, m_bitlen
- 32);
79 memmove(x
+ 2, x
+ 1, (mlen
- 1) * sizeof *x
);
81 a1
= br_i32_word(x
, m_bitlen
- 32);
82 b0
= br_i32_word(m
, m_bitlen
- 32);
85 * We estimate a divisor q. If the quotient returned by br_div()
87 * -- If a0 == b0 then g == 0; we want q = 0xFFFFFFFF.
89 * -- if g == 0 then we set q = 0;
90 * -- otherwise, we set q = g - 1.
91 * The properties described above then ensure that the true
92 * quotient is q-1, q or q+1.
94 g
= br_div(a0
, a1
, b0
);
95 q
= MUX(EQ(a0
, b0
), 0xFFFFFFFF, MUX(EQ(g
, 0), 0, g
- 1));
98 * We subtract q*m from x (with the extra high word of value 'hi').
99 * Since q may be off by 1 (in either direction), we may have to
100 * add or subtract m afterwards.
102 * The 'tb' flag will be true (1) at the end of the loop if the
103 * result is greater than or equal to the modulus (not counting
104 * 'hi' or the carry).
108 for (u
= 1; u
<= mlen
; u
++) {
109 uint32_t mw
, zw
, xw
, nxw
;
113 zl
= MUL(mw
, q
) + cc
;
114 cc
= (uint32_t)(zl
>> 32);
118 cc
+= (uint64_t)GT(nxw
, xw
);
120 tb
= MUX(EQ(nxw
, mw
), tb
, GT(nxw
, mw
));
124 * If we underestimated q, then either cc < hi (one extra bit
125 * beyond the top array word), or cc == hi and tb is true (no
126 * extra bit, but the result is not lower than the modulus). In
127 * these cases we must subtract m once.
129 * Otherwise, we may have overestimated, which will show as
130 * cc > hi (thus a negative result). Correction is adding m once.
132 chf
= (uint32_t)(cc
>> 32);
134 over
= chf
| GT(clow
, hi
);
135 under
= ~over
& (tb
| (~chf
& LT(clow
, hi
)));
136 br_i32_add(x
, m
, over
);
137 br_i32_sub(x
, m
, under
);